are solved by group of students and teacher of NEET, which is also the largest student Your product is 2 NO (nitrogenmonooxide). Answers of The equilibrium constant for the reaction N2 (g) O2 - 2NO(g) is 4×10 power minus 4 at 2000 K In presence of a catalyst, equilibrium is attained ten times faster. The equilibrium constant for the reaction N2(g) + O2(g) ⇋  2NO(g) at temperature T is 4 × 10–4. (1) 40× 10 power minus 4 (2) 4 × 10 power minus 4 (3) 4× 10 power minus 3 (4) difficult to compute without more data? If the answer is not available please wait for a while and a community member will probably answer this Check the sources for some more information on the equilibrium constant. We insert those values into the equation: K = (0.50 * 0.50) / (0.020) K = 0.50² / 0.020. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. The value of Kc for the reaction NO(g)gives ½N2(g) +½O2 at the same temperature is (A) 2.5 × 10² (B) 50 (C) 4 x 104 Therefore, the equilibrium constant, in presence of the catalyst, at 2000 K is? Your reactants are N2 (nitrogen) and O2 (oxygen). The equilibrium constant (Kc ) for the reaction N2(g)+O2(g)→ 2NO(g) at temperature T is 4x10^-4. By continuing, I agree that I am at least 13 years old and have read and Chemical Equilibrium and Equilibrium Constant, Equilibrium - Characteristics of Equilibrium constant. You can study other questions, MCQs, videos and tests for NEET on EduRev and even discuss your questions like The equilibrium constant (Kc ) for the reaction N2(g)+O2(g)→ 2NO(g) at temperature T is 4x10^-4. Question bank for NEET. Therefore, the equilibrium constant in the presence of the catalyst of 2000 k is: The equilibrium constant for the reaction N2 + O2<--> 2NO is 1.69 × 10^?3 at 2300 K. A mixture consisting of 2 mol of nitrogen and 1.0 mol of oxygen is heated to 2300 K at 1 bar and allowed to come to equilibrium. Hope this makes it clear for you. The equilibrium constant for the reaction N2(g) + O2(g) + 2NO(g) at temperature T is 4x10^⁴. agree to the. Apart from being the largest NEET community, EduRev has the largest solved EduRev is a knowledge-sharing community that depends on everyone being able to pitch in when they know something. K = 12.5. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. (1) 40× 10 power minus 4 (2) 4 × 10 power minus 4 (3) 4× 10 power minus 3 (4) difficult to compute without more data? Sep 23,2020 - The equilibrium constant for the reaction N2 (g) O2 - 2NO(g) is 4×10 power minus 4 at 2000 K In presence of a catalyst, equilibrium is attained ten times faster. K1 and K2 are equilibrium constant for reactions (i) and (ii) N2(g) + O2(g) ⇋ 2NO(g) .....(i), If the equilibrium constant for N2(g) + O2(g) ⇋ 2NO(g) is K, equilibrium constant. Therefore, the equilibrium constant, in presence of the catalyst, at 2000 K is? asked Oct 16, 2018 in Chemistry by Sagarmatha ( 54.4k points) equilibrium AIPMT 2015: If the equilibrium constant for N2(g) + O2(g) <=> 2NO(g) is K, the equilibrium constant for (1/2) N2 (g) + (1/2) O2 (g) <=> NO(g) will The equilibrium constant for the reaction N2(g) + O2(g) ⇋ 2NO(g) at temperature T is 4 × 10^–4. The equilibrium constant for the reaction, N2(g) + O2(g) ⇋ 2NO(g) is 4 × 10^-4 at 2000K. Therefore, the equilibrium constant, in presence of the catalyst, at 2000 K is? Click hereto get an answer to your question ️ The equilibrium constant for the reaction, N2(g) + O2(g) = 2NO(g) is 4 × 10^-4 at 2000 k. In the presence of a catalyst, the equilibrium is attained ten times faster. community of NEET. Therefore, the equilibrium constant, in presence of the catalyst, at 2000 K is? The Questions and Calculate the mole fraction of NO at equilibrium. The value of Kc for the reaction : NO(g) ⇋1/2 N 2(g) + 1/2 O2(g) at the same temperature is. This discussion on The equilibrium constant for the reaction N2 (g) O2 - 2NO(g) is 4×10 power minus 4 at 2000 K In presence of a catalyst, equilibrium is attained ten times faster. For the reaction, N2(g) + O2(g) ⇋ 2NO(g), the equilibrium constant is K1. Reactant needs to be placed above product. is done on EduRev Study Group by NEET Students. (1) 40× 10 power minus 4 (2) 4 × 10 power minus 4 (3) 4× 10 power minus 3 (4) difficult to compute without more data? 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